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In trigonometry, the law of cosines (also known as the cosine formula or cosine rule) relates the lengths of the sides of a plane triangle to the cosine of one of its angles. Using notation as in Fig. 1, the law of cosines says

where γ denotes the angle contained between sides of lengths a and b and opposite the side of length c.

The law of cosines generalizes the Pythagorean theorem, which holds only for right triangles: if the angle γ is a right angle (of measure 90° or π/2 radians), then cos γ = 0, and thus the law of cosines reduces to the Pythagorean theorem:

The law of cosines is useful for computing the third side of a triangle when two sides and their enclosed angle are known, and in computing the angles of a triangle if all three sides are known.

By changing which sides of the triangle play the roles of a, b, and c in the original formula, one discovers that the following two formulas also state the law of cosines:

Though the notion of the cosine was not yet developed in his time, Euclid's Elements, dating back to the 3rd century BC, contains an early geometric theorem almost equivalent to the law of cosines. The case of obtuse triangle and acute triangle (corresponding to the two cases of negative or positive cosine) are treated separately, in Propositions 12 and 13 of Book 2. Trigonometric functions and algebra (in particular negative numbers) being absent in Euclid's time, the statement has a more geometric flavor:

Proposition 12
In obtuse-angled triangles the square on the side subtending the obtuse angle is greater than the squares on the sides containing the obtuse angle by twice the rectangle contained by one of the sides about the obtuse angle, namely that on which the perpendicular falls, and the straight line cut off outside by the perpendicular towards the obtuse angle.

—Euclid's Elements, translation by Thomas L. Heath.^[1]

Using notation as in Fig. 2, Euclid's statement can be represented by the formula

This formula may be transformed into the law of cosines by noting that CH = (CB) cos(π − γ) = −(CB) cos γ. Proposition 13 contains an entirely analogous statement for acute triangles.

The theorem was popularized in the Western world by François Viète in the 16th century. At the beginning of the 19th century, modern algebraic notation allowed the law of cosines to be written in its current symbolic form.

Contents 1 Applications 2 Proofs 2.1 Using the distance formula 2.2 Using trigonometry 2.3 Using the Pythagorean theorem 2.4 Using Ptolemy's theorem 2.5 By comparing areas 2.6 Using geometry of the circle 3 Vector formulation 4 Isosceles case 5 Analog for tetrahedra 6 Law of cosines in non-Euclidean geometry 7 See also 8 References 9 External links

Applications [edit]

The theorem is used in triangulation, for solving a triangle or circle, i.e., to find (see Figure 3):

• the third side of a triangle if one knows two sides and the angle between them:

• the angles of a triangle if one knows the three sides:

• the third side of a triangle if one knows two sides and an angle opposite to one of them (one may also use the Pythagorean theorem to do this if it is a right triangle):

These formulas produce high round-off errors in floating point calculations if the triangle is very acute, i.e., if c is small relative to a and b or γ is small compared to 1. It is even possible to obtain a result slightly greater than one for the cosine of an angle.

The third formula shown is the result of solving for a the quadratic equation a² − 2ab cos γ + b² − c² = 0. This equation can have 2, 1, or 0 positive solutions corresponding to the number of possible triangles given the data. It will have two positive solutions if b sin γ < c < b, only one positive solution if c ≥ b, and no solution if c < b sin γ. These different cases are also explained by the Side-Side-Angle congruence ambiguity.

Proofs [edit]

Using the distance formula [edit]

Consider a triangle with sides of length a, b, c, where γ is the measurement of the angle opposite the side of length c. We can place this triangle on the coordinate system by plotting

By the distance formula, we have

Now, we just work with that equation:

An advantage of this proof is that it does not require the consideration of different cases for when the triangle is acute vs. obtuse.

Using trigonometry [edit]

Drop the perpendicular onto the side c to get (see Fig. 4)

(This is still true if α or β is obtuse, in which case the perpendicular falls outside the triangle.) Multiply through by c to get

By considering the other perpendiculars obtain

Adding the latter two equations gives

Subtracting the first equation from the last one we have

which simplifies to

This proof uses trigonometry in that it treats the cosines of the various angles as quantities in their own right. It uses the fact that the cosine of an angle expresses the relation between the two sides enclosing that angle in any right triangle. Other proofs (below) are more geometric in that they treat an expression such as a cos γ merely as a label for the length of a certain line segment.

Many proofs deal with the cases of obtuse and acute angles γ separately.

Using the Pythagorean theorem [edit]

Case of an obtuse angle. Euclid proves this theorem by applying the Pythagorean theorem to each of the two right triangles in Fig. 5. Using d to denote the line segment CH and h for the height BH, triangle AHB gives us

and triangle CHB gives us

Expanding the first equation gives us

Substituting the second equation into this, the following can be obtained

This is Euclid's Proposition 12 from Book 2 of the Elements.^[2] To transform it into the modern form of the law of cosines, note that

Case of an acute angle. Euclid's proof of his Proposition 13 proceeds along the same lines as his proof of Proposition 12: he applies the Pythagorean theorem to both right triangles formed by dropping the perpendicular onto one of the sides enclosing the angle γ and uses the binomial theorem to simplify.

Another proof in the acute case. Using a little more trigonometry, the law of cosines by applying can be deduced by using the Pythagorean theorem only once. In fact, by using the right triangle on the left hand side of Fig. 6 it can be shown that:

using the trigonometric identity

Remark. This proof needs a slight modification if b < a cos(γ). In this case, the right triangle to which the Pythagorean theorem is applied moves outside the triangle ABC. The only effect this has on the calculation is that the quantity b − a cos(γ) is replaced by a cos(γ) − b. As this quantity enters the calculation only through its square, the rest of the proof is unaffected.

Note. This problem only occurs when β is obtuse, and may be avoided by reflecting the triangle about the bisector of γ.

Observation. Referring to Fig. 6 it's worth noting that if the angle opposite side a is α then:

This is useful for direct calculation of a second angle when two sides and an included angle are given.

Using Ptolemy's theorem [edit]

Referring to the diagram, triangle ABC with sides AB = c, BC = a and AC = b is drawn inside its circumcircle as shown. Triangle ABD is constructed congruent to triangle ABC with AD = BC and BD = AC. Perpendiculars from D and C meet base AB at E and F respectively. Then:

Now the law of cosines is rendered by a straightforward application of Ptolemy's theorem to cyclic quadrilateral ABCD:

Plainly if angle B is 90°, then ABCD is a rectangle and application of Ptolemy's theorem yields the Pythagorean theorem:

By comparing areas [edit]

One can also prove the law of cosines by calculating areas. The change of sign as the angle γ becomes obtuse makes a case distinction necessary.

Recall that

• a², b², and c² are the areas of the squares with sides a, b, and c, respectively;
• if γ is acute, then ab cos γ is the area of the parallelogram with sides a and b forming an angle of ;
• if γ is obtuse, and so cos γ is negative, then −ab cos γ is the area of the parallelogram with sides a and b forming an angle of .

Acute case. Figure 7a shows a heptagon cut into smaller pieces (in two different ways) to yield a proof of the law of cosines. The various pieces are

• in pink, the areas a², b² on the left and the areas 2ab cos γ and c² on the right;
• in blue, the triangle ABC, on the left and on the right;
• in grey, auxiliary triangles, all congruent to ABC, an equal number (namely 2) both on the left and on the right.

The equality of areas on the left and on the right gives

Obtuse case. Figure 7b cuts a hexagon in two different ways into smaller pieces, yielding a proof of the law of cosines in the case that the angle γ is obtuse. We have

• in pink, the areas a², b², and −2ab cos γ on the left and c² on the right;
• in blue, the triangle ABC twice, on the left, as well as on the right.

The equality of areas on the left and on the right gives

The rigorous proof will have to include proofs that various shapes are congruent and therefore have equal area. This will use the theory of congruent triangles.

Using geometry of the circle [edit]

Using the geometry of the circle, it is possible to give a more geometric proof than using the Pythagorean theorem alone. Algebraic manipulations (in particular the binomial theorem) are avoided.

Case of acute angle γ, where a > 2b cos γ. Drop the perpendicular from A onto a = BC, creating a line segment of length b cos γ. Duplicate the right triangle to form the isosceles triangle ACP. Construct the circle with center A and radius b, and its tangent h = BH through B. The tangent h forms a right angle with the radius b (Euclid's Elements: Book 3, Proposition 18; or see here), so the yellow triangle in Figure 8 is right. Apply the Pythagorean theorem to obtain

Then use the tangent secant theorem (Euclid's Elements: Book 3, Proposition 36), which says that the square on the tangent through a point B outside the circle is equal to the product of the two lines segments (from B) created by any secant of the circle through B. In the present case: BH² = BC BP, or

Substituting into the previous equation gives the law of cosines:

Note that h² is the power of the point B with respect to the circle. The use of the Pythagorean theorem and the tangent secant theorem can be replaced by a single application of the power of a point theorem.

Case of acute angle γ, where a < 2b cos γ. Drop the perpendicular from A onto a = BC, creating a line segment of length b cos γ. Duplicate the right triangle to form the isosceles triangle ACP. Construct the circle with center A and radius b, and a chord through B perpendicular to c = AB, half of which is h = BH. Apply the Pythagorean theorem to obtain

Now use the chord theorem (Euclid's Elements: Book 3, Proposition 35), which says that if two chords intersect, the product of the two line segments obtained on one chord is equal to the product of the two line segments obtained on the other chord. In the present case: BH² = BC BP, or

Substituting into the previous equation gives the law of cosines:

Note that the power of the point B with respect to the circle has the negative value −h².

Case of obtuse angle γ. This proof uses the power of a point theorem directly, without the auxiliary triangles obtained by constructing a tangent or a chord. Construct a circle with center B and radius a (see Figure 9), which intersects the secant through A and C in C and K. The power of the point A with respect to the circle is equal to both AB² − BC² and AC·AK. Therefore,

which is the law of cosines.

Using algebraic measures for line segments (allowing negative numbers as lengths of segments) the case of obtuse angle (CK > 0) and acute angle (CK < 0) can be treated simultaneously.

Vector formulation [edit]

The law of cosines is equivalent to the formula

in the theory of vectors, which expresses the dot product of two vectors in terms of their respective lengths and the angle they enclose.

Proof of equivalence. Referring to Figure 10, note that

and so we may calculate:

The law of cosines formulated in this notation states:

which is clearly equivalent to the above formula from the theory of vectors.

Isosceles case [edit]

When a = b, i.e., when the triangle is isosceles with the two sides incident to the angle γ equal, the law of cosines simplifies significantly. Namely, because a² + b² = 2a² = 2ab, the law of cosines becomes

or

Analog for tetrahedra [edit]

An analogous statement begins by taking α, β, γ, δ to be the areas of the four faces of a tetrahedron. Denote the dihedral angles by etc. Then^[3]

Law of cosines in non-Euclidean geometry [edit]

A version of the law of cosines also holds in non-Euclidean geometry. In spherical geometry, a triangle is defined by three points u, v, and w on the unit sphere, and the arcs of great circles connecting those points. If these great circles make angles A, B, and C with opposite sides a, b, c then the spherical law of cosines asserts that each of the following relationships hold:

In hyperbolic geometry, a pair of equations are collectively known as the hyperbolic law of cosines. The first is

where sinh and cosh are the hyperbolic sine and cosine, and the second is

Like in Euclidean geometry, one can use the law of cosines to determine the angles A, B, C from the knowledge of the sides a, b, c. However, unlike Euclidean geometry, the reverse is also possible in each of the models of non-Euclidean geometry: the angles A, B, C determine the sides a, b, c.

See also [edit]

• Half-side formula
• Law of sines
• Law of tangents
• List of trigonometric identities
• Mollweide's formula
• Solution of triangles
• Triangulation

References [edit]

External links [edit]

• Hazewinkel, Michiel, ed. (2001), "Cosine theorem", Encyclopedia of Mathematics, Springer, ISBN 978-1-55608-010-4 
• Several derivations of the Cosine Law, including Euclid's at cut-the-knot
• Interactive applet of Law of Cosines